MATH SOLVE

4 months ago

Q:
# 11 black balls and 14 white balls are placed in an urn. two balls are then drawn in succession. what is the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball?

Accepted Solution

A:

[tex] |\Omega|=25\cdot24=600\\

|A|=11\cdot14+14\cdot13=154+182=336\\\\

P(A)=\dfrac{336}{600}=\dfrac{14}{25}=56\% [/tex]

|A|=11\cdot14+14\cdot13=154+182=336\\\\

P(A)=\dfrac{336}{600}=\dfrac{14}{25}=56\% [/tex]