A box has a volume of 128 feet3. The length is twice the width and the height is the same as the width. What are the dimensions of the box?
Accepted Solution
A:
Let the width of the box = XThe height would also be XThe length would be 2XVolume = L x W x H128 = X * X Β *2xSimplify:128 = x^2 * 2x128 = x^3 * 2Divide both sides by 2:x^3 = 64Take the cubic root of both sides:X = 4The width = 4 feetThe height = 4 feet The length = 8 feet.